Walls and Ceilings - Interior Wall Angle
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olson2334
04-27-05, 05:10 PM
I have a bathroom that is supposed to be box shaped but i would like to angel the doorway into it instead to give it some shape. I don't know how to figure the angel out when i cut the necessary studs for building my walls. Can someone explain how to calculate an angel when building an interior wall or point me to a site where I can find step by step instructions on how to do this? Thanks for the help.
XSleeper
04-27-05, 05:54 PM
Angel? or Angle? You'll have to talk to the guy upstairs if you need help with angels. ;)
But regarding your wall, usually something like that might be framed at a 45 degree angle. (actually 135 degrees). How big will your door be? Will there need to be any electrical boxes or light switches in the framing on this angled wall?
You can easily figure out a 135 degree wall. Let's say you'll be installing a 2-8 door that requires a rough opening of 34". On each side of the door, you have a king stud and a jack stud, so add 6". Assuming no wall switch will be in this wall, the minimum interior measurement of that wall would be 40". Chalk some lines on the floor to indicate where that corner of the room would be if it was a square corner. Then do some math: Your 40" measurement will represent the hypotenuse of a 45-45-90 triangle. The pythagorean theorum states: A squared + B squared = C squared, where C is the hypotenuse. So you would take 40x40 (C squared), which is 1600. (1600 = A squared + B squared) So divide 1600 by 2 which is 800. Find the square root of 800, which is 28.28". So the interior side of your 135 degree wall framing would begin 28 1/4" from your imaginary square corner that you chalked out on the floor. Then connect those marks and you should have a 40" long wall.
If you have a scientific calculator, a faster way to figure it is by using trigonometry: Hypotenuse x 45 cos (then hit "equals") = the adjacent sides.
But regarding your wall, usually something like that might be framed at a 45 degree angle. (actually 135 degrees). How big will your door be? Will there need to be any electrical boxes or light switches in the framing on this angled wall?
You can easily figure out a 135 degree wall. Let's say you'll be installing a 2-8 door that requires a rough opening of 34". On each side of the door, you have a king stud and a jack stud, so add 6". Assuming no wall switch will be in this wall, the minimum interior measurement of that wall would be 40". Chalk some lines on the floor to indicate where that corner of the room would be if it was a square corner. Then do some math: Your 40" measurement will represent the hypotenuse of a 45-45-90 triangle. The pythagorean theorum states: A squared + B squared = C squared, where C is the hypotenuse. So you would take 40x40 (C squared), which is 1600. (1600 = A squared + B squared) So divide 1600 by 2 which is 800. Find the square root of 800, which is 28.28". So the interior side of your 135 degree wall framing would begin 28 1/4" from your imaginary square corner that you chalked out on the floor. Then connect those marks and you should have a 40" long wall.
If you have a scientific calculator, a faster way to figure it is by using trigonometry: Hypotenuse x 45 cos (then hit "equals") = the adjacent sides.
olson2334
04-28-05, 02:49 AM
well it is pretty darn obvious spelling is not one of my stong point. :) Then again, i could use some help from the guy upstairs with this project.
Thanks for the reply.
Math, on the other hand, is a tad better and I understand your post and look forward to giving it a try tonight. Thanks again.
Thanks for the reply.
Math, on the other hand, is a tad better and I understand your post and look forward to giving it a try tonight. Thanks again.
marksr
04-28-05, 03:18 AM
Angel? or Angle? You'll have to talk to the guy upstairs if you need help with angels. ;)
But regarding your wall, usually something like that might be framed at a 45 degree angle. (actually 135 degrees). How big will your door be? Will there need to be any electrical boxes or light switches in the framing on this angled wall?
You can easily figure out a 135 degree wall. Let's say you'll be installing a 2-8 door that requires a rough opening of 34". On each side of the door, you have a king stud and a jack stud, so add 6". Assuming no wall switch will be in this wall, the minimum interior measurement of that wall would be 40". Chalk some lines on the floor to indicate where that corner of the room would be if it was a square corner. Then do some math: Your 40" measurement will represent the hypotenuse of a 45-45-90 triangle. The pythagorean theorum states: A squared + B squared = C squared, where C is the hypotenuse. So you would take 40x40 (C squared), which is 1600. (1600 = A squared + B squared) So divide 1600 by 2 which is 800. Find the square root of 800, which is 28.28". So the interior side of your 135 degree wall framing would begin 28 1/4" from your imaginary square corner that you chalked out on the floor. Then connect those marks and you should have a 40" long wall.
If you have a scientific calculator, a faster way to figure it is by using trigonometry: Hypotenuse x 45 cos (then hit "equals") = the adjacent sides.
Never knew a angle wall was so complicated. Fortunatly laying it out on the floor [or on paper] with chaulk or pencil works for me. :)
But regarding your wall, usually something like that might be framed at a 45 degree angle. (actually 135 degrees). How big will your door be? Will there need to be any electrical boxes or light switches in the framing on this angled wall?
You can easily figure out a 135 degree wall. Let's say you'll be installing a 2-8 door that requires a rough opening of 34". On each side of the door, you have a king stud and a jack stud, so add 6". Assuming no wall switch will be in this wall, the minimum interior measurement of that wall would be 40". Chalk some lines on the floor to indicate where that corner of the room would be if it was a square corner. Then do some math: Your 40" measurement will represent the hypotenuse of a 45-45-90 triangle. The pythagorean theorum states: A squared + B squared = C squared, where C is the hypotenuse. So you would take 40x40 (C squared), which is 1600. (1600 = A squared + B squared) So divide 1600 by 2 which is 800. Find the square root of 800, which is 28.28". So the interior side of your 135 degree wall framing would begin 28 1/4" from your imaginary square corner that you chalked out on the floor. Then connect those marks and you should have a 40" long wall.
If you have a scientific calculator, a faster way to figure it is by using trigonometry: Hypotenuse x 45 cos (then hit "equals") = the adjacent sides.
Never knew a angle wall was so complicated. Fortunatly laying it out on the floor [or on paper] with chaulk or pencil works for me. :)